By Mark Clark

Starting ALGEBRA: CONNECTING strategies via functions exhibits scholars the best way to follow conventional mathematical abilities in real-world contexts. The emphasis on ability construction and purposes engages scholars as they grasp algebraic innovations, challenge fixing, and communique abilities. scholars the way to remedy difficulties generated from lifelike functions, rather than studying suggestions with no conceptual figuring out. The authors have built numerous key principles to make thoughts actual and brilliant for college students. First, they emphasize robust algebra talents. those abilities aid the purposes and increase pupil comprehension. moment, the authors combine purposes, drawing on sensible facts to teach scholars why they should recognize and the way to use math. The functions support scholars increase the talents had to clarify the that means of solutions within the context of the appliance. 3rd, the authors strengthen key techniques as scholars growth throughout the path. for instance, the distributive estate is brought in actual numbers, lined whilst scholars are studying the way to multiply a polynomial by way of a relentless, and eventually whilst scholars the way to multiply a polynomial by way of a monomial. those thoughts are strengthened via functions within the textual content. final, the authors' process prepares scholars for intermediate algebra via together with an creation to fabric resembling services and period notation in addition to the final bankruptcy that covers linear and quadratic modeling.

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Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. indd 9 25/10/10 8:54 PM 10 CHAPTER R Review of Prealgebra PRACTICE PROBLEM FOR EXAMPLE 9 Subtract the integers. a. 8 2 15 b. 7 2 Θ 210 Ι Example 10 Rising and falling temperatures a. If the temperature is 25°F and the temperature rises by 8°F, then what is the new temperature? b. If the temperature is 212°F and the temperature drops by 2°F, then what is the new temperature? F 120 100 80 60 40 20 0 –20 –40 C 50 40 30 20 10 0 –10 –20 –30 –40 SOLUTION a.

___ 18 16 b. ___ 36 25 c. ___ 70 ▼ Copyright 2011 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. 2 21 Operations with Fractions SOLUTION a. The GCF for 9 and 18 is 9. Divide out 9 from the numerator and denominator of the fraction.

227 c. ____ 5 9 23 The answer is positive, since the two integers have the same sign. PRACTICE PROBLEM FOR EXAMPLE 13 Divide the following integers. a. 20 4 Θ 24 Ι 216 b. ____ 28 c. Θ 227 Ι 4 3 Keep in mind that division by 0 means that 0 is the divisor or is in the denominator. 0 When 0 is the dividend, such as 0 4 16 or ___ , the answer is 0. It is important to note 16 that division by zero is undefined (sometimes, mathematicians say the result of such 16 an operation “does not exist” or “DNE”).